In how much time would the simple interest on a certain sum be $0.125$ times the principal at $10 %$ per annum?

15

months

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12

months

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18

months

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21

months

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Solution

The correct option is C $15$ months
Let sum be $x$ .
$\Rightarrow$ $S . I . = 0.125 x = \frac{1}{8} x$
We know $Time = \frac{100 \times S . I .}{P \times R}$
$= \frac{100 \times \frac{1}{8} x}{x \times 10}$
$= \frac{100 \times x}{x \times 8 \times 10}$
Therefore, $Time = \frac{5}{4} = 1 \frac{1}{4}$ years $= 15$ Months

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(iii) Principal $= R s .4500$ , Rate of Interest $= 4 %$ per annum and Time $= 6$ months.
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(v) Principal $= R s .1000$ , Rate of Interest $= 10 %$ per annum and Time $= 73$ days.

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In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?

The correct option is C 15 monthsLet sum be x.⇒ S.I.=0.125x=18xWe know Time=100×S.I.P×R=100×18xx×10=100×xx×8×10Therefore, Time=54=114 years =15 Months

In how much time would the simple interest on a certain sum be $0.125$ times the principal at $10 %$ per annum?