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Effect on Kc

In hte follow...

Question

In hte following reaction
$2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)$
the equilibrium is not attained. The rate of forward reaction is greater than that of backward reaction. Thus, which of the following is the correct relation between $K_{p}$ and $Q_{p}$ ?

K_{p} = Q_{p}

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Q_{p} > K_{p}

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Q_{p} < K_{p}

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K_{p} = Q_{p} = 1

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Solution

The correct option is C $Q_{p} < K_{p}$
As the rate of forward reaction is greater than that of backward reaction, the reaction must proceed in the forward direction. Hence, $Q_{P} < K_{P}$

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