In humans, polydactyly (i.e, presence of extra fingers and toes) is determined by a dominant autosomal allele (P) and the normal condition is determined by a recessive allele (p). Find out the possible genotypes of family members 1, 2 and 3 in the given pedigree.

1 PP, 2 Pp, 3 - pp

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1 PP, 2 PP, 3 - pp

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1 Pp, 2 PP, 3 - Pp

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1 Pp, 2 Pp, 3 - pp

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Solution

The correct option is C 1 Pp, 2 Pp, 3 - pp
Given pedigree chart for polydactyly (autosomal dominant trait) can be explained as follows

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Similar questions

P

| x | < 1

\frac{d}{d x} [1 + \frac{p}{q} x + \frac{p (p + q)}{2!} {(\frac{x}{q})}^{2} + \frac{p (p + q) (p + 2 q)}{3!} {(\frac{x}{q})}^{3} . . . . \infty] =

P P^{^{'}}

b^{2} x^{2} + a^{2} y^{2} = a^{2} b^{2}

P P^{^{'}^{2}}

P P^{^{'}}

\times

^{A}

\times

\times

\times

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