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Energy Levels

In Hydrogen a...

Question

In Hydrogen and Hydrogen like atoms, the ratio of difference of energies $E_{2} n - E_{n}$ and $E_{2} n E_{2} n$ varies with its atomic number $z$ and $n$ as-

\frac{z^{2}}{n^{2}}

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\frac{z^{4}}{n^{4}}

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\frac{z}{n}

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\frac{n^{2}}{z^{2}}

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Solution

The correct option is B $\frac{z^{2}}{n^{2}}$
$\begin{matrix} Energy. of e^{-} according to Bohr's postalate = - 13 \cdot 6 \frac{z^{2}}{n^{2}} So, E_{2 n} - E_{n} (difference) and E_{n} \propto \frac{z^{2}}{n^{2}} \end{matrix}$

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