Question

In hydrogen atom electron revolves a round nucleus in circular orbit of radius $5\times {10}^{-11}m$ at a speed $2.2\times {10}^{6}m/s$. Then orbital current will be

• A. $3.2mA$
• B. $2.42mA$
• C. $1.12mA$
• D. $0.02mA$

Answer 1

The correct option is C $1.12mA$

Given:

radius $=5\times {10}^{-11}m$

Speed $=2.2\times {10}^{6}m/s$

We know

$i$=$\frac{q}{t}=\frac{e}{\left(\frac{2\pi r}{v}\right)}$

$i$=$\frac{ev}{2\pi r}$

$i$=$\frac{2.2\times {10}^6\times 1.6\times {10}^{-19}}{2\times T\times 5\times {10}^{-11}}$

$i$=$1.12\times {10}^{-3}amp$

$i$=$1.12mA$

$[\begin{array}{cc}c]& 1.12mA\end{array}$