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Byju's Answer
Standard XII
Chemistry
1900's Physics and Wave
in hydrogen a...
Question
in hydrogen atom,energy of first excited state is -3.4eV.then find out KE of same orbit of hydrogen atom
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Similar questions
Q.
In hydrogen atom, energy of first excited state is
−
3.4
e
V
. Then find out the
K
E
of the same orbit of hydrogen atom.
Q.
In the Hydrogen atom, the energy of the first excited state is
−
3.4
e
V
. Then find out KE of the same orbit of
the Hydrogen atom:
Q.
In a hydrogen atom, the energy of the first excited state is - 3.4 eV. Find out the K.E. of the same orbit of the hydrogen atom.
Q.
Potential energy is
−
27.2
e
V
in second orbit of
H
e
+
then calculate, double of total energy in first excited state of hydrogen atom:-
Q.
Total energy of an electron in the ground state of hydrogen atom is
−
13.6
e
V
. Its total energy, when hydrogen atom is in the first excited state, is:
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