Question

In hydrogen atom, the electron moves in an orbit of radius ${5\times 10}^{-11}$ m with a speed of ${2.2\times 10}^6$ m/sec. Calculate the equivalent current.

Answer 1

$r=5\times {10}^{-11}$

$v=2.2\times {10}^{6}m/s$

time period,

$T=\frac{2\pi r}{v}$

current = charge passing per unit time

$I=\frac{q}{t}$

$t=\frac{2\pi r}{v}$

$I=\frac{q}{2\pi r}.v$

$=\frac{1.6\times {10}^{-19}\times 2.2\times {10}^6}{5\times {10}^{-11}\times 2\pi }$

$=\frac{1.6\times 2.2}{5\times 2\pi }\times {10}^{-2}$

$=1.12\times {10}^{-3}A$

$I=1.12mA$