Question

In I-node list eight direct pointers, one indirect pointer and one double indirect pointer, block size is 512 Bytes and each entry size is 16 Bytes, then maximum file size can be (in KB) _____.

Answer 1

$\text{Number of entries in one block}=\frac{512Bytes}{16Bytes}=2^{5}entries$
$\text{Total number of blocks}=\left[\right(8+\left(2^5\right)+\left(2^5{)}^2\right]blocks$
$=[8+2^5+2^{10}]blocks$
$=1064Blocks$
$\text{Maximum File size = Total number of blocks}{}^{\ast }\text{Block size}$
= 1064${}^{\ast }$ 512 Bytes
= 532 KB