In iso-electronic species O 2- F -and N a - size is affected by-A- Valence principal quantum numberB- Electron-electron interactions in the outer orbitalsC- Nuclear charge Z of the elementD- None of the factors because their size is the same

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Isoelectronic Species

In iso-electr...

Question

In iso-electronic species $O^{2 -}$ , $F^{-}$ and $N a^{+}$ , size is affected by:

Nuclear charge (Z) of the element

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Valence principal quantum number

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Electron-electron interactions in the outer orbitals

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None of the factors because their size is the same

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Solution

The correct option is A Nuclear charge (Z) of the element
Size of an iso-electronic species increases with a decrease in the nuclear charge Z.
The order of increasing nuclear charge is: $O^{2 -}$ < $F^{-}$ < $N a^{+}$
So the order of increasing size is:
$N a^{+}$ < $F^{-}$ < $O^{2 -}$

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In iso-electronic species O2−, F− and Na+, size is affected by:

The correct option is A Nuclear charge (Z) of the elementSize of an iso-electronic species increases with a decrease in the nuclear charge Z. The order of increasing nuclear charge is: O2− < F− < Na+ So the order of increasing size is: Na+ < F− < O2−

In iso-electronic species $O^{2 -}$ , $F^{-}$ and $N a^{+}$ , size is affected by:

The correct option is A Nuclear charge (Z) of the element
Size of an iso-electronic species increases with a decrease in the nuclear charge Z.
The order of increasing nuclear charge is: $O^{2 -}$ < $F^{-}$ < $N a^{+}$
So the order of increasing size is:
$N a^{+}$ < $F^{-}$ < $O^{2 -}$