In isosceles triangle ABC; AB=AC and $∠ B = 70^{o}$ , find $∠ A$

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Solution

Given, AB = AC, $∠ B = 70$
$∠ B = ∠ C = 70^{\circ}$ (Isosceles triangle property)
Sum of angles,
$∠ A + ∠ B + ∠ C = 180$
$∠ A + 70 + 70 = 180$
$∠ A = 40^{\circ}$

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