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Question
In Joly's defferential steam calorimeter, 3 g of an ideal gas is contained in a rigid closed sphere at 20∘C. The sphere is heated by steam at 100∘C and it is found that an extra 0.095 g of steam has condensed into water as the temperature of the gas becomes constant. Calucate the specific heat capacity of the gas in J g−1 K−1. The latent heat of vaporization of water = 540 cal g−1
In Joly's defferential steam calorimeter, 3 g of an ideal gas is contained in a rigid closed sphere at 20∘C. The sphere is heated by steam at 100∘C and it is found that an extra 0.095 g of steam has condensed into water as the temperature of the gas becomes constant. Calucate the specific heat capacity of the gas in J g−1 K−1. The latent heat of vaporization of water = 540 cal g−1
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Solution
In Jolly's differential steam calorimeter,
Cv = m2Lm1(θ3−θ1)
M2 = Mass of steam condensed
= 0.095 g
L = 540cal/g=540×4.2J/g
M1 = Mass of gas present = 3 g
θ=20∘C,θ2=100∘C
⇒Cv=0.095×540×4.23×(100−20)
= 0.89 = 0.9 J/ g-K
In Jolly's differential steam calorimeter,
Cv = m2Lm1(θ3−θ1)
M2 = Mass of steam condensed
= 0.095 g
L = 540cal/g=540×4.2J/g
M1 = Mass of gas present = 3 g
θ=20∘C,θ2=100∘C
⇒Cv=0.095×540×4.23×(100−20)
= 0.89 = 0.9 J/ g-K
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