Question

In $K^{+}{F}^{-}$ ionic radius of $F^{-}$ is more while atomic radius of $K^{+}$ is:

• A. less than $F^{-}$
• B. more than $F^{-}$
• C. equal of $F^{-}$
• D. none of these

Answer 1

Answer: (A)

less than $F^{-}$

Anion has a large size than cation as in cation no. of $p^{+}>$ no. of $e^{-}$

due to which $e^{-}$ pull is more and thus size is small.

Whereas in anion no. of $e^{-}>$ no. of $p^{+}$

due to which $e^{-}$ pull is not that strong hence size is bigger than the neutral due to interelectronic repulsions as well.