In K,Rb and Cs the during decreasing order of reducing power in gaseous state is:-
A
K>Rb>Cs
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B
Cs>Rb>K
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C
K<Cs<Rb
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D
Rb>Cs>K
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Solution
The correct option is BCs>Rb>K The reducing power of any element can be judged by its tendency to release an electron. Higher the tendency to release electron, higher will be the tendency to get oxidized and higher will be the reducing power of that element. We know that down the group IP decreases as size increases. So the elements present down the group will readily get oxidised. So they will possess a higher reducing power. So the correct sequence is B