Question

In $KBr$ crystal structure, the number of the first nearest neighbor of $K^{+}$ ions is:

Answer 1

$KBr$ structure

$K^{+}$ forms FCC lattice

$B{r}^{-}$ occupies octahedral voids.

Nearest neighbours of $K^{+}$ will be $6$ $B{r}^{-}$ ions at a distance of $\frac{a}{2}$.