In KI solution, $I_{2}$ readily dissolves and forms :

I^{-}

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K I_{2}

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K I_{2}^{-}

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K I_{3}

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Solution

The correct option is D $K I_{3}$
In KI solution, $I_{2}$ readily dissolves and forms $K I_{3}$ which contains polyhalide ion $I_{3}^{-}$

$K I + I_{2} \to K I_{3}$

Due to this, iodine is partly soluble in water but highly soluble in the $K I$ solution.

So, the correct option is $D$

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