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Question

In Kjeldahl’s method for the estimation of nitrogen present in a soil sample, the ammonia evolved from 0.75 g of sample neutralized 10 mL of 1 M H2SO4. The percentage of nitrogen in the soil is:

A
37.33
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B
45.33
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C
35.33
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D
43.33
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Solution

The correct option is A 37.33
This can be solved on the basis of law of chemical equivalance
According to which;
gram equivalents of NH3=gram equivalents of H2SO4
moles×nf=M×V×nf1000
n×1=1×10×21000
n=201000=2×102
Now,
1 mole of NH3 contains 1 mole of `N`.
2×102 moles of NH3 contains 2×102 moles of nitrogen.
Hence,
mass of `N `= moles× molar mass
= 2×102×14
= 0.28 g
% of `N` =0.280.75×100

= 283×4= `37.33 %`

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