wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In Kjeldahl’s method for the estimation of nitrogen present in a soil sample, the ammonia evolved from 0.75 g of sample neutralized 10 mL of 1 M H2SO4. The percentage of nitrogen in the soil is:

A
37.33
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
45.33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
35.33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
43.33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 37.33
This can be solved on the basis of law of chemical equivalance
According to which;
gram equivalents of NH3=gram equivalents of H2SO4
moles×nf=M×V×nf1000
n×1=1×10×21000
n=201000=2×102
Now,
1 mole of NH3 contains 1 mole of `N`.
2×102 moles of NH3 contains 2×102 moles of nitrogen.
Hence,
mass of `N `= moles× molar mass
= 2×102×14
= 0.28 g
% of `N` =0.280.75×100

= 283×4= `37.33 %`

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon