Question

In $K{O}_2$, the nature of oxygen species and the oxidation state of oxygen atom are, respectively.

• A. Superoxide and $-1$
• B. Superoxide and $-\frac{1}{2}$
  
• C. Peroxide and $-\frac{1}{2}$
• D. Oxide and $-2$

Answer 1

The correct option is B Superoxide and $-\frac{1}{2}$

In $K{O}_2$, the nature of oxygen species and the oxidation state of oxygen atom are, superoxide and $-1/2$ respectively.
Superoxide ion is $O_2^{-}$.

Let X be an oxidation state of oxygen. The oxidation state of K is +1.
$+1+2\left(X\right)=0$

$2X=-1$

$X=-\frac{1}{2}$