In $L - R$ circuit shown in diagram, reading of ammeter is $i_{1}$ . Now, a diamagnetic material is inserted into the inductor, then the new reading of ammeter is $i_{2},$ will be

i_{1} > i_{2}

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i_{2} > i_{1}

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i_{1} = i_{2}

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cannot say about

i_{1} a n d i_{2},

it depends upon value of R

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Solution

The correct option is B $i_{2} > i_{1}$
If diamagnetic material is introduced,
$L ↓ \Rightarrow Z ↓ \Rightarrow i ↑$

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In L−R circuit shown in diagram, reading of ammeter is i1. Now, a diamagnetic material is inserted into the inductor, then the new reading of ammeter is i2, will be

The correct option is B i2>i1If diamagnetic material is introduced, L ↓ ⇒ Z ↓ ⇒ i ↑

In $L - R$ circuit shown in diagram, reading of ammeter is $i_{1}$ . Now, a diamagnetic material is inserted into the inductor, then the new reading of ammeter is $i_{2},$ will be

The correct option is B $i_{2} > i_{1}$
If diamagnetic material is introduced,
$L ↓ \Rightarrow Z ↓ \Rightarrow i ↑$