In laboratory, $H_{2} O_{2}$ is prepared by the action of:

cold

H_{2} S O_{4}

and

B a O_{2}

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aqueous alkali on

N a_{2} O_{2}

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M n O_{2}

and cold

H_{2} S O_{4}

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dilute

H C l

and

M n O_{2}

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Solution

The correct option is B cold $H_{2} S O_{4}$ and $B a O_{2}$
In laboratory, $H_{2} O_{2}$ is preparedby the following reaction:

$B a O_{2} .8 H_{2} O + H_{2} S O_{4} \to B a S O_{4} + H_{2} O_{2} + 8 H_{2} O$

Suggest Corrections

Similar questions

In lab $H_{2} O_{2}$ is prepared by

H_{2} O_{2}

(M n O_{2})

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

M n O_{2}

H_{2} O_{2} ?

M n O_{2}

M n O_{2} (s) \to 2 H_{2} O (l) + M n C l_{2} (a q) + C l_{2} (g)

H C l

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