Question

In Lathyrus odoratus, if double heterozygous purple-flowered plants are crossed then what would be the probability of double homozygous white-flowered plants?

• A. $\frac{4}{16}$
• B. $\frac{3}{16}$
• C. $\frac{2}{16}$
• D. $\frac{1}{16}$

Answer 1

Answer: (D)

$\frac{1}{16}$

According to the dihybrid, if the double heterozygous plants are crossed then the gametes formed will be- AB, ab, Ab, aB. The genotype of the double homozygous white flowering plant will be aabb because white is the recessive gene. The probability will be 1/16 according to the dihybrid cross ratio.

	Ab	AB	aB	ab
Ab	AAbb	AABb	AaBb	Aabb
AB	AABb	AABB	AaBB	AaBb
aB	aABb	AaBB	aaBB	aaBb
ab	aAbb	aABb	aaBb	aabb

So, the correct option is '1/16'