In LCR series circuit, an alternating e.m.f. 'e' and current 'i' are given by the equations $e = 100 sin (100 t)$ volt, $i = 100 sin (100 + \frac{π}{3})$ mA. The average power dissipated in the circuit will be

100

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10

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5

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2.5

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Solution

The correct option is A $2.5$ W
The formula for average power in series LCR circuit is given by:
$P = \frac{E_{0} I_{0}}{2} cos ϕ$
Substituting the values, we have:
$P = \frac{100 \times 0.1}{2} cos \frac{π}{3} = 2.5 W$

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In LCR series circuit, an alternating e.m.f. 'e' and current 'i' are given by the equations e=100sin(100t)volt, i=100sin(100+π3)mA. The average power dissipated in the circuit will be

The correct option is A 2.5WThe formula for average power in series LCR circuit is given by:P=E0I02cosϕSubstituting the values, we have:P=100×0.12cosπ3=2.5W

In LCR series circuit, an alternating e.m.f. 'e' and current 'i' are given by the equations $e = 100 sin (100 t)$ volt, $i = 100 sin (100 + \frac{π}{3})$ mA. The average power dissipated in the circuit will be

The correct option is A $2.5$ W
The formula for average power in series LCR circuit is given by:
$P = \frac{E_{0} I_{0}}{2} cos ϕ$
Substituting the values, we have:
$P = \frac{100 \times 0.1}{2} cos \frac{π}{3} = 2.5 W$