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Question

In lens displacement method lateral magnification obtained are 2 and 0.5. if separation between position of lenses is 30 cm, then focal length of lens is

A
30 cm
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B
20 cm
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C
15 cm
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D
10 cm
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Solution

The correct option is B 20 cm
Since, from the question we get that the magnification are given as 2&0.5 , if we take the object distance is u and the image distance is V . So: 2=vu;0.5=4v
Hence 20.5=vuuv or 1.5=v2u2vu(vu)(v+u)vu=15 we know vu=30 cm(30)(v+u)vu=151012=(v+u)vu
from eq n1f=1v1u ; vel Rnow that f=uvv+v1012=1ff=210120 cm Hence obtion B is correct.

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