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Question

In LiI Crystal, I ions form a cubical closest packed arrangement and Li+ ions occupy octahedral holes. What is the relationship between the edge-length of the unit cells and the radii of the I ions? Calculate the limiting ionic radii of Li+ and I if a = 600pm.


Solution

From question
2r++2r=600pmr++r=300pm(1)
Since, Li+ ions occupy octahedral hole
So, for octahedral hole
r+r=0.414(ii)
From equation (I)and equation (II)
r(r+r+1)=300r×(0.414+1)=300r=3001.414=212.164(r+r=0.414)r+=212.164×0.414=r+=87.84pm

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