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Construction of Triangle Whose Perimeter and Ratio of the Sides Are Given

In Δ LMN , l ...

Question

In ∆LMN, l(LM) = 6.2 cm, m $∠$ LMN = 60^°, l(MN) = 4 cm. Construct ∆LMN.

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Solution

Steps of constructions:

(1) Draw seg LM of length 6.2 cm.
(2) Draw ray MA such that ∠LMA = 60°.
(3) Draw an arc of 4 cm from the vertex M, cutting the ray MA at N.

Therefore, △LMN is the required triangle.

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∆

LMN in base MN = 7 cm,

∠

°

-

Q. Draw triangles according to the following measures.

(1) In ∆PQR, l (PQ) = 4.9 cm, l (QR) = 5.3 cm, m∠Q = 50°
(2) In ∆LMN, l (LM) = 4 cm, l (MN) = 5 cm, m∠M = 70°
(3) In ∆DEF, l (DE) = l (DF) = 6 cm, m∠D = 40°
(4) In ∆BCD, m∠B = 110°, l (BC) = l (BD) = 6.2 cm

Q. Draw the triangles according tot he measures given below.

(1) In ∆LMN, l (LM) = 6 cm, l (MN) = 8 cm, l (LN) = 7 cm
(2) In ∆PQR, l (PQ) = l (PR) = 5.9 cm, l (QR) = 3.3 cm
(3) In ∆VJN, l (JN) = l (VN) = 6.2 cm

Q. Construct a right triangle

L M N

∠ M = 90^{\circ}, M N = 4 c m

L N = 6.2 c m

∆

~

∆

∆

ABC, AB = 5.1 cm,

∠

°

∠

°

\frac{A C}{L N} = \frac{3}{5}

; then construct

△

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