In manufacturing industries, loss is usually taken to be proportional to the square of the deviation from a target. If the loss is Rs. 4900 for a deviation of 7 units, what would be the loss in Rupees for a deviation of 4 units from the target?

400

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1600

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2800

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1600
Loss $= k d^{2}$ For duration of 7 units

$4900 = k (7)^{2} \Rightarrow k = 100$

Loss $= k d^{2}$ For duration of 4 units

$= k (4)^{2} \Rightarrow 16 k = 1600$

Suggest Corrections

Similar questions

A labourer is required to make 100 units in a day but actually, he is able to make 80 units in a day. Thus, there is a negative deviation of 20 units.

(i) What steps should be taken to reduce the deviation?

(ii) Which values are missing in the above paragraph?

Q. The data are received from a firm for advertisement and sale as given below:

	Sales (in crores)	Advertisement (in crores)
Mean	$40$	$6$
Standard Deviation	$10$	$1.5$
Coefficient of correlation $r = 0.9$

If the firm fixed the target for sale as

60

crores rupees, then calculate the amount for advertisement.

If the sum of the squares of deviations for 10 observations taken from their mean is 2.5, then write thevalue of standard deviation.

Q. Let the characteristic strength be defined as that value, below which not more than 50% of the results are expected to fail. Assuming a standard deviation of 4 MPa, the target mean strength (in MPa) to be considered in the mix design of a M25 concrete would be

Q. The target mean strength

f_{c m}

for concrete mix design obtained from the characteristic strength

f_{c k}

and standard deviation

σ

as defined in IS 456-2000 is

Join BYJU'S Learning Program

In manufacturing industries, loss is usually taken to be proportional to the square of the deviation from a target. If the loss is Rs. 4900 for a deviation of 7 units, what would be the loss in Rupees for a deviation of 4 units from the target?

The correct option is C 1600Loss =kd2 For duration of 7 units 4900=k(7)2 ⇒k=100 Loss =kd2 For duration of 4 units =k(4)2 ⇒16k=1600

The correct option is C 1600
Loss $= k d^{2}$ For duration of 7 units

$4900 = k (7)^{2} \Rightarrow k = 100$

Loss $= k d^{2}$ For duration of 4 units

$= k (4)^{2} \Rightarrow 16 k = 1600$