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Question

In measuring the sides of a rectangle, errors of 5% and 3% in excess are made. The error percentage in the calculated area is ____.


A

7.15%

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B

6.25%

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C

8.15%

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D

8.35%

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Solution

The correct option is C

8.15%


Let actual sides of the rectangle be 'l' and 'b' respectively.

The measured sides are (l+0.05l) and (b+0.03b) i.e. 1.05l and 1.03b
Therefore, measured area =(1.05l)(1.03b)

Actual area =lb
Error in area =1.0815lblb=0.0815lb
% error=0.0815lblb×100%=8.15%


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