In measuring the sides of a rectangle, one side taken 10% in excess and the other 20% in deficit Find the error percent in area calculated from the measurement.

12% deficit

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10% deficit

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12% excess

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None of these

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Solution

The correct option is A 12% deficit
$S i n c e s i d e_{1} \times s i d e_{2} = a r e a$

$∴ E r r o r % i n a r e a$

$= (x + y + \frac{x y}{100}) %$

$= (10 - 20 - \frac{10 \times 20}{100}) %$

$H e r e, x = 10 a n d y = - 20$

$= - 12 % i . e . 12 % d e f i c i t$

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In measuring the sides of a rectangle, one side taken 10% in excess and the other 20% in deficit Find the error percent in area calculated from the measurement.

The correct option is A 12% deficit Since side1×side2=area ∴ Error % in area =(x+y+xy100)% =(10−20−10×20100)% Here, x=10 and y=−20 =−12% i.e. 12% deficit

The correct option is A 12% deficit
$S i n c e s i d e_{1} \times s i d e_{2} = a r e a$

$∴ E r r o r % i n a r e a$

$= (x + y + \frac{x y}{100}) %$

$= (10 - 20 - \frac{10 \times 20}{100}) %$

$H e r e, x = 10 a n d y = - 20$

$= - 12 % i . e . 12 % d e f i c i t$