In measuring the volume of a cork piece, initial water level in a measuring cylinder is kept at 50.2 ml. When a piece of iron is dipped into the water, the level reads 61.5 mI. When the same piece of iron tied to the given cork piece is dipped into the water, the level reads 68.1 ml. Find the volume (in cm $^{3}$ ) of iron piece.

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Solution

Volume of iron = volume after iron is added - volume without iron
$1 m i l l i m i t r e = 10^{- 6} m^{3}$
$V = 61.5 - 50.2 = 11.3 m l = 11.3 \times 10^{- 6} m^{3}$

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Volume of iron = volume after iron is added - volume without iron1 millimitre=10−6m3V=61.5−50.2=11.3ml=11.3×10−6m3

Volume of iron = volume after iron is added - volume without iron
$1 m i l l i m i t r e = 10^{- 6} m^{3}$
$V = 61.5 - 50.2 = 11.3 m l = 11.3 \times 10^{- 6} m^{3}$