Question

In methyl alcohol solution, bromine reacts with ethylene to yield $BrC{H}_{2}C{H}_{2}OC{H}_3$ in addition to 1, 2-dibromoethane because

• A. The ion formed initially may react with $B{r}^{-}$ or $C{H}_{3}OH$
• B. The methyl alcohol solvates the bromine
• C. The reaction follows Markownikoff's rule
• D. This is a free-radical mechanism

Answer 1

The correct option is A The ion formed initially may react with $B{r}^{-}$ or $C{H}_{3}OH$

$C{H}_2=C{H}_2+B{r}_2\stackrel{C{H}_{3}OH}{\to }$
$C{H}_2-C{H}_2+Br-C{H}_2-C{H}_2-O-C{H}_3||BrBr$