In $M g C l_{2}$ , the oxidation number of chlorine is:

+ 1

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+ 2

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- 1

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0

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Solution

The correct option is C $- 1$
In $M g C l_{2}$ , oxidation number of $C l$ is:

$\Rightarrow 2 + 2 x = 0$

$\Rightarrow x = - 1$ .

Hence, option C is correct.

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