In Millikan’s oil drop experiment, an oil drop of radius $r$ and charge $Q$ is held in equilibrium between the plates of a charged parallel plate capacitor when the potential difference is $V$ . To keep a drop of radius $2 r$ and charge $2 Q$ in equilibrium between the plates ,the potential difference required will be

8 V

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4 V

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2 V

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1 V

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Solution

The correct option is B $4 V$
Use Force balance
4/3pir^3dg=Q*V/l.
l is distance between plates.

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The correct option is B 4VUse Force balance4/3*pi*r^3*d*g=Q*V/l.l is distance between plates.

The correct option is B $4 V$
Use Force balance
4/3pir^3dg=Q*V/l.
l is distance between plates.