In mixture A and B components show -ve deviation as:

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A-B interaction is weaker than A-A and B-B interaction

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A-B interaction is strong than A-A and B-B interaction

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Solution

Explanation:
In a mixture component A and component B Shows negative Deviation as, $Δ V_{m i x i n g} < 0$
i.e. For Negative Deviation, $Δ V_{m i x i n g} = 0$ , $Δ H_{m i x i n g} = - v e$
Because, the forces of attraction between components A and B is greater.
Due to that the tendency of escaping of molecules AB from solution becomes less than that of pure liquids.
A-B attractive forces is greater than A-A and B-B attractive forces.
Hence, option (D) is correct.

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Question 21
On the basis of information given below mark the correct option.
Information
(i) In bromoethane and chloroethane mixture intermolecular interactions of A-A and B-B type are nearly same as A-B type interactions.
(ii) In ethanol and acetone mixture A-A or B-B type intermolecular interactions are stronger than A-B type interactions.
(iii) In chloroform and acetone mixture A-A or B-B type intermolecular interactions are weaker than A-B type interactions.
(a) Solution (ii) and (iii) will follow Raoult's law
(b) Solution (i) will follow Raoult's law
(c) Solution (ii) will show negative deviation from Raoult's law
(d) Solution (iii) will show positive deviation from Raoult's law

Q. On the basis of information given below mark the correct option information.
(I) In bromoethane and chloroethane mixture intermolecular interactions of A-A and B-B type are nearly same as A-B type interactions.
(II) In ethanol and acetone mixture A-A or B-B type intermolecular interactions are stronger than A-B type interactions.
(III) In chloroform and acetone mixture A-A or B-B type intermolecular interactions are weaker than A-B type interactions.

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