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Question
In moving from A to B along an electric field line, the work done by the electric field on an electron is 6.4×10−19J. If ϕ1 and ϕ2 are equipotential surfaces, then the potential difference Vc−VA is :
In moving from A to B along an electric field line, the work done by the electric field on an electron is 6.4×10−19J. If ϕ1 and ϕ2 are equipotential surfaces, then the potential difference Vc−VA is :
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Solution
The correct option is C 4V
Work done will be equal to change in potential energy
WeL=q(Vi−Vf)
or 6.4×10−19=−1.6×10−19(VA−VB)
or VA−VB=−4V
or VA−VC=−4V(∵VB=VC)
or VC−VA=4V
Work done will be equal to change in potential energy
WeL=q(Vi−Vf)
or 6.4×10−19=−1.6×10−19(VA−VB)
or VA−VB=−4V
or VA−VC=−4V(∵VB=VC)
or VC−VA=4V
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