In N2 - 2H2O - NH4- - NO-2- N is -

The correct options are A oxidised B reducedOxidation involves an increase in oxidation number nbsp;while reduction involves a decrease in oxidation number. ...

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Standard IX

Chemistry

Calculating Oxidation Number

In N2 + 2H2...

Question

In $N_{2} + 2 H_{2} O \to N H_{4}^{+} + N O_{2}^{-}$ , $N$ is :

oxidised

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reduced

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hydrated

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none of these

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Solution

The correct options are
A oxidised
B reduced
Oxidation involves an increase in oxidation number while reduction involves a decrease in oxidation number.
$N_{2} + 2 H_{2} O \to N H_{4}^{+} + N O_{2}^{-}$
0 -3 +3
So, here we can see that both oxidation and reduction of N happens.

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Similar questions

Q. Out of the following redox reactions, disproportionation is not shown in:

I

{N H}_{4} {N O}_{3} Δ - \to N_{2} O + 2 H_{2} O

I I

{N H}_{4} {N O}_{2} Δ - \to N_{2} + 2 H_{2} O

I I I

P {C l}_{5} Δ - \to P {C l}_{3} + {C l}_{2}

N H_{4}^{+} + 30_{2} N i t r o s o m o n a s - -------- \to

____

+ 2 H_{2} O + E n e r g y

Q. The unit of rate constant for the reaction

2 H_{2} + 2 NO \to 2 H_{2} O + N_{2}

which has
Rate

= K [H_{2}] [N O]^{2},

is:

Q. The unit of rate constant for the reaction,

2 H_{2} + 2 N O \to 2 H_{2} O + N_{2}

which has

r a t e = k [H_{2}] [N O]^{2}

, is:

Q. If true enter 1, else enter 0.

{N O}_{2}^{-}

interferes in the 'ring test' of

{N O}_{3}^{-}

. A chemical method of removal of

{N O}_{2}^{-}

is boiling the mixture with

N H_{4} C l

{N O}_{2}^{-}

is decomposed as follows:

N a N O_{2} + N H_{4} C l △ ⟶ N a C l + N_{2} ↑ + 2 H_{2} O

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In N2+2H2O→NH+4+NO−2, N is :

The correct options are A oxidised B reducedOxidation involves an increase in oxidation number while reduction involves a decrease in oxidation number.N2+2H2O→NH+4+NO−2 0 -3 +3So, here we can see that both oxidation and reduction of N happens.

In $N_{2} + 2 H_{2} O \to N H_{4}^{+} + N O_{2}^{-}$ , $N$ is :

The correct options are
A oxidised
B reduced
Oxidation involves an increase in oxidation number while reduction involves a decrease in oxidation number.
$N_{2} + 2 H_{2} O \to N H_{4}^{+} + N O_{2}^{-}$
0 -3 +3
So, here we can see that both oxidation and reduction of N happens.