In $N a F$ or $M g F_{2}$ , which is formed more easily?

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Solution

$N a F$ is more ionic than $M g F_{2}$ . The $N a^{+}$ ion is larger than the $M g^{2 +}$ ion, and it also has the lower charge. The anion ( $F^{-}$ ) is common in both the compounds. So, in terms of Fajan's rules, $N a F$ should be more ionic between the two and hence formed more easily.

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