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Question

In neon gas discharge tube 2.9*10^18 Ne+ ions move to the right through a cross section of the tube each second while 1.2*10^18 electrons move to the left this time. the electronic charge is 1.6*10^-19 coulomb. what is the net electric current in the tube?

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Solution

in a discharge tube +ve ions carry q units of charge in t second from anode to cathode and -ve carriers (electrones ) carry the same amount of charge from cathode to anode in t second
the current in the tube is I=q/t + q'/t'
hence in this question current I =[(2.9*10^18 * 1.6*10^-19) /1]+[(1.2*10^18*1.6*10^-19)/1]
= 0.66 A towards right

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