In non-cyclic photophosphorylation, PS I is reduced by
In non-cyclic photophosphorylation, PS I is reduced by
The correct option is A Electron from PS II
The photosystem II complex replaced its lost electrons from an external source; however, the two other electrons are not returned to photosystem II as they would in the analogous cyclic pathway. Instead, the still-excited electrons are transferred to a photosystem I complex, which boosts their energy level to a higher level using a second solar photon. The highly excited electrons are transferred to the acceptor molecule, but this time is passed on to an enzyme called Ferredoxin-NADP^+ reductase which uses them to catalyse the reaction (as shown):
- NADP+ + 2H+ + 2e− → NADPH + H+
This consumes the H+ ions produced by the splitting of water, leading to a net production of 1/2O2, ATP, and NADPH+H+ with the consumption of solar photons and water.
So, the correct option is 'Option A'.
The photosystem II complex replaced its lost electrons from an external source; however, the two other electrons are not returned to photosystem II as they would in the analogous cyclic pathway. Instead, the still-excited electrons are transferred to a photosystem I complex, which boosts their energy level to a higher level using a second solar photon. The highly excited electrons are transferred to the acceptor molecule, but this time is passed on to an enzyme called Ferredoxin-NADP^+ reductase which uses them to catalyse the reaction (as shown):
- NADP+ + 2H+ + 2e− → NADPH + H+
This consumes the H+ ions produced by the splitting of water, leading to a net production of 1/2O2, ATP, and NADPH+H+ with the consumption of solar photons and water.
So, the correct option is 'Option A'.
