Question

In NPN transistor the collector current is $10$ mA. If $90\%$ of electrons emitted reach the collector, then?

• A. Emitter current will be $9$ mA
• B. Emitter current will be $11.1$ mA
• C. Base current will be $0.1$ mA
• D. Base current will be $0.01$ mA

Answer 1

The correct option is B Emitter current will be $11.1$ mA

90% emitted elctrons reach the collector,

Hence,

$\frac{I_c}{I_e}=0.9$

Since,$I_c=10$mA,

Therefore $I_e=10/0.9=11.11$mA

Hence, the emitter current will be 11 mA.