In $O F_{2}$ , oxygen has hybridisation of:

s p

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s p^{2}

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s p^{3}

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s p^{3} d

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Solution

The correct option is D $s p^{3}$
In $O F_{2}$ , oxygen has $2$ bond pairs and $2$ lone pairs and hence hybridization is $s p^{3}$ .

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