In one alloy there is 60% gold in its total mass, while in another alloy it is 35%. 12 kg of the first alloy was melted together with 8 kg of the second one to form a third alloy. Find the percentage of gold in the new alloy.

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Solution

Amount of gold in 1st alloy = 0.6* 12 = 7.2 kg. Amount of gold in 2nd alloy = 0.35* 8 =2.8 kg.
required % age of gold = $\frac{(7.2 + 2.8)}{(12 + 8)} \times 100$ = 50 %.

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In one alloy there is 60% gold in its total mass, while in another alloy it is 35%. 12 kg of the first alloy was melted together with 8 kg of the second one to form a third alloy. Find the percentage of gold in the new alloy.

Amount of gold in 1st alloy = 0.6* 12 = 7.2 kg. Amount of gold in 2nd alloy = 0.35* 8 =2.8 kg. required % age of gold = (7.2+2.8)(12+8)×100 = 50 %.

Amount of gold in 1st alloy = 0.6* 12 = 7.2 kg. Amount of gold in 2nd alloy = 0.35* 8 =2.8 kg.
required % age of gold = $\frac{(7.2 + 2.8)}{(12 + 8)} \times 100$ = 50 %.