In one metre long open pipe what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz

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Solution

The correct option is C third
In case of open pipe,
$n = \frac{N}{2 l}$
where $N =$ order of harmonics = order of vibration $\Rightarrow N = \frac{n \times 2 l}{v}$

$= \frac{480}{330} \times 2 \times 1 = 3$ (here $v = 330 m / s$ )

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In one metre long open pipe what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz

The correct option is C thirdIn case of open pipe, n=N2l where N= order of harmonics = order of vibration ⇒N=n×2lv=480330×2×1=3 (here v=330m/s)

The correct option is C third
In case of open pipe,
$n = \frac{N}{2 l}$
where $N =$ order of harmonics = order of vibration $\Rightarrow N = \frac{n \times 2 l}{v}$

$= \frac{480}{330} \times 2 \times 1 = 3$ (here $v = 330 m / s$ )