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Self Induction

In one second...

Question

In one second, a current of 10 A changes through a coil. The induced emf is 10V, then, self-inductance of the coil is

A

2H

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B

5H

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C

1H

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D

0.5H

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Solution

The correct option is C 1H
From Faradays law the induced emf is $e = L \frac{d i}{d t}$
Given, $d i = 10 A, d t = 1 s, e = 10 V$
$∴ 10 = L \frac{10}{1}$
$\Rightarrow L = 1 H$

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