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Question

In open-die forging, a disc of diameter 200 mm and height 60 mm is compressed without any barreling effect. The final diameter of the disc is 400 mm. The true strain is

A
1.986
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B
1.686
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C
1.386
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D
0.602
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Solution

The correct option is C 1.386
Since, volume of disc remains constant during the process, Hence

πD214×l1=πD224l2

D21l1=D22l2

2002×60=4002×l2

l2=15mm

Change in length=l1l2

=6015=45 mm
Strain:
ε=l1l2l2=4515=3

True strain
εT=ln(1+ε)=ln(1+3)

=ln4=1.386

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