Question

In order to create a $0.500M$ solution of $HCl$ for use in a laboratory experiment, how much distilled water must be used to dilute $100mL$ of a $3.00MHCl$ solution?

• A. $600mL$
• B. $500mL$
• C. $150mL$
• D. $100mL$

Answer 1

Answer: (B)

$500mL$

$Molarity=\frac{Moles}{Volume}$

Moles of $HCl$ present $=100\times {10}^{-3}\times 3=0.3$

Required molarity $=0.5$

$\therefore 0.5=\frac{0.3}{Volume}$

$\therefore Volume=0.6$ $L=600$ $mL$

Here, Total volume $=600$ $mL$

Initial volume $=100$ $mL$

Here, $500$ $mL$ of distilled water should be added for required concentration.