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Standard IX

Chemistry

Solutions

In order to d...

Question

In order to determine solubility of sodium iodide (NaI), 150g of saturated solution of sodium iodide(NaI) is evaporated to dryness at $25^{0}$ C. At this stage 90 g of NaI is obtained. Find the solubility of NaI in water at $25^{\circ}$ C.

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Solution

Weight of saturated solution = 150 g

Weight of NaI = 90 g

Weight of water = (Weight of saturated solution) - (Weight of NaI)

= 150 - 90 = 60 g

Solubility of NaI = $\frac{W e i g h t o f N a l}{W e i g h t o f W a t e r} \times 100$

$\Rightarrow$ $\frac{90}{60} \times 100$ $\Rightarrow$ 150g

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In order to determine solubility of sodium iodide (NaI), 150g of saturated solution of sodium iodide(NaI) is evaporated to dryness at 250C. At this stage 90 g of NaI is obtained. Find the solubility of NaI in water at 25∘C.

Weight of saturated solution = 150 g Weight of NaI = 90 g Weight of water = (Weight of saturated solution) - (Weight of NaI) = 150 - 90 = 60 g Solubility of NaI = Weight of NalWeight of Water×100 ⇒ 9060×100 ⇒ 150g

In order to determine solubility of sodium iodide (NaI), 150g of saturated solution of sodium iodide(NaI) is evaporated to dryness at $25^{0}$ C. At this stage 90 g of NaI is obtained. Find the solubility of NaI in water at $25^{\circ}$ C.

Weight of saturated solution = 150 g

Weight of NaI = 90 g

Weight of water = (Weight of saturated solution) - (Weight of NaI)

= 150 - 90 = 60 g

Solubility of NaI = $\frac{W e i g h t o f N a l}{W e i g h t o f W a t e r} \times 100$

$\Rightarrow$ $\frac{90}{60} \times 100$ $\Rightarrow$ 150g