In order to establish an instantaneous displacement current of 1mA in the space between the plates of 2μF parallel plate capacitor, the potential difference need to apply is
A
100Vs−1
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B
200Vs−1
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C
300Vs−1
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D
500Vs−1
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Solution
The correct option is D500Vs−1 The displacement current during charging/discharging of a capacitor is, Id=C(dVdt) 1×10−3=2×10−6(dVdt) ∴dVdt=1×1032=500Vs−1