In order to obtain a magnification of, - 0.6 (minus 0.6) with a concave mirror, the object must be placed : (a) at the focus (b) between pole and focus (c) between focus and centre of curvature (d) beyond the centre of curvature

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Solution

A magnification of -0.6 means that the image is real, inverted and diminished. So the object should be placed beyond the centre of curvature and the correct choice is (d).

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Q. A concave mirror produces magnification of +4. The object is placed:

(a) at the focus
(b) between focus and centre of curvature
(c) between focus and pole
(d) beyond the centre of curvature

Q. If a magnification of, −1 (minus one) is to be obtained by using a converging mirror, then the object has to be placed:

(a) between pole and focus
(b) at the centre of curvature
(c) beyond the centre of curvature
(d) at infinity

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Question 30
Draw ray diagrams showing the image formation by a concave mirror when an object is placed

(a) between pole and focus of the mirror
(b) between focus and centre of curvature of the mirror
(c) at centre of curvature of the mirror
(d) a little beyond centre of curvature of the mirror
(e) at infinity

The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?

(a) Between the principal focus and the centre of curvature

(b) At the centre of curvature

(d) Between the pole of the mirror and its principal focus.

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