Question

In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration 5 $\frac{g}{4}$ relative to the rope. The tension in the rope is (take g = 10 $m{s}^{-2}$)

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Let T be the tension in the rope and a the acceleration of rope.

The absolute acceleration of man is, therefore, $(\frac{5g}{4}-a)$.

Equations of motion for mass and man gives:
T-100g=100a ...............(i)
T-60g=60$(\frac{5g}{4}-a)$ ...............(ii)

Solving Eqs (i) and (ii), we get $T=\frac{4875}{4}N$