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Standard XII

Physics

General Gravity Problem

in order to r...

Question

in order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. he climbs the rope with an acceleration 5 g/ 4

1432 N

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928 N

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1218 N

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642 N

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Solution

The correct option is C 1218 N
$T - 100 g = 100 a$
$- T - + 60 g = - 60 (\frac{5}{4} g - a) - ----------------------- -$
$- 40 g = 160 a - 75 g$

$\Rightarrow 160 a = 35 g$
$\Rightarrow a = \frac{35}{160} \times 10 = \frac{35}{16} m / s^{2}$
$T = 100 g + 100 a$
$= 1000 + 100 \times \frac{35}{16}$
$= \frac{4000 + 875}{4} = \frac{4875}{4} = 1218.75 N$
$∴ T = 1218.75 N$
Hence, option $C$ is correct answer.

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in order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. he climbs the rope with an acceleration 5 g/ 4

The correct option is C 1218 N T−100g=100a−T−+60g=−60(54g−a)–––––––––––––––––––––––––−40g=160a−75g⇒160a=35g⇒a=35160×10=3516m/s2T=100g+100a=1000+100×3516=4000+8754=48754=1218.75N∴T=1218.75NHence, option C is correct answer.