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Question

In order to supplement daily diet, a person wishes to take some X and some wishes Y tablets. The contents of iron, calcium and vitamins in X and Y (in mg/tablet) are given as below

TabletsIronCalciumVitaminX632Y234

The person needs atleast 18 mg of iron, 21 mg of calcium and 16 mg of vitamins. The price of each tablet of X and Y is Rs 2 and R1, respectively. How many tablets of each should the person take in order to stisfy the above requirement at the minimum cost?

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Solution

Let the person takes x units of tablet X and y units of tablet Y.
So, from the given information,we have
6x+2y183x+y9.....(i)3x+3y21x+y7.....(ii)
and 2x+4y16x+2y8.....(iii)
Also, we know that here, x0,y0....(iv)
The price of each tablet of X and Y is Rs 2 and Rs 1. respectively.
So, the corresponding LPP is minimise Z=2x+y, subject to 3x+y9,x+y7,x+2y8,x0,y0.
From the shaded graph, we see that for the shown unbounded rgion, we have coordinates of corner points A,B,C and D as (8,0),(6,1),(1,6), and (0,9), respectively.
[on solving x+2y =8 and x+y =7, we get x =6, y =1 and on solving 3x+y =9 and x+y =7, we get x=1, y =6]

Corner pointsValue of Z =2x+y(8,0)16(6,1)13(1,6)8Minimum(0,9)9
Thus, we see that 8 is the minimum value of Z at the corner point (1,6). Here, we see that the feasible region is unbounded. Therefore, 8 may or may not be the minimum value of Z.
To decide this issue, we graph the inequality
2x+y < 8...(v)
and check whether the resulting open half has points in common with feasible region or not. If it has common point. then 8 will not be the minimum value of Z, otherwise 8 will be the minimum value of Z.
Thus, from the graph it is clear that, it has no common point.
Therefore, Z=2x+y has 8 as minimum value subject to the given constraints.
Hence, the person should take 1 unit of X table and 6 units of Y tablets to satisfy the given requirements and at the minimum cost of Rs 8.


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